Record Class OrderBy

java.lang.Object
java.lang.Record
top.magstar.framework.database.query.OrderBy
public record OrderBy(String field, OrderBy.Direction direction) extends Record
排序条件类。

用于构建 SQL 查询的 ORDER BY 子句。

Since:
1.0.0
Version:
1.0.0
Author:
Berry_so

  • Constructor Details

    • OrderBy

      public OrderBy(String field, OrderBy.Direction direction)
      构造一个排序条件。
      Parameters:
      field - 字段名
      direction - 排序方向

  • Method Details

    • asc

      public static OrderBy asc(String field)
      创建升序排序条件。
      Parameters:
      field - 字段名
      Returns:
      排序条件对象

    • desc

      public static OrderBy desc(String field)
      创建降序排序条件。
      Parameters:
      field - 字段名
      Returns:
      排序条件对象

    • field

      public String field()
      获取字段名。
      Returns:
      字段名

    • direction

      public OrderBy.Direction direction()
      获取排序方向。
      Returns:
      排序方向

    • toString

      @NotNull public @NotNull String toString()
      Returns a string representation of this record class. The representation contains the name of the class, followed by the name and value of each of the record components.
      Specified by:
      toString in class Record
      Returns:
      a string representation of this object

    • hashCode

      public final int hashCode()
      Returns a hash code value for this object. The value is derived from the hash code of each of the record components.
      Specified by:
      hashCode in class Record
      Returns:
      a hash code value for this object

    • equals

      public final boolean equals(Object o)
      Indicates whether some other object is "equal to" this one. The objects are equal if the other object is of the same class and if all the record components are equal. All components in this record class are compared with Objects::equals(Object,Object).
      Specified by:
      equals in class Record
      Parameters:
      o - the object with which to compare
      Returns:
      true if this object is the same as the o argument; false otherwise.